类类型
写法:
export interface ConstructorOf<T> {
new(...args: any[]): T;
}
应用:
class BeeKeeper {
hasMask: boolean = true;
}
class ZooKeeper {
nametag: string = "Mikle";
}
class Animal {
numLegs: number = 4;
}
class Bee extends Animal {
keeper: BeeKeeper = new BeeKeeper();
}
class Lion extends Animal {
keeper: ZooKeeper = new ZooKeeper();
}
function createInstance<A extends Animal>(c: ConstructorOf(A)): A {
return new c();
}
createInstance(Lion).keeper.nametag;
createInstance(Bee).keeper.hasMask;
函数返回类型
写法:
type ReturnType<T extends (...args: any[]) => any> = T extends (...args: any[]) => infer R ? R : any;
参数类型
写法:
type Parameters<T> = T extends (...args: infer R) => any ? R : any;
应用:
type T0 = Parameters<() => string>; // []
type T1 = Parameters<(s: string) => void>; // [string]
type T2 = Parameters<(<T>(arg: T) => T)>; // [unknown]
类型推导infer
参考
https://blog.csdn.net/KlausLily/article/details/108878205
题目:https://github.com/LeetCode-OpenSource/hire/blob/master/typescript_zh.md
interface Action<T> {
payload?: T;
type: string;
}
class EffectModule {
count = 1;
message = "hello!";
delay(input: Promise<number>) {
return input.then(i => ({
payload: `hello ${i}!`,
type: 'delay'
}));
}
setMessage(action: Action<Date>) {
return {
payload: action.payload!.getMilliseconds(),
type: "set-message"
};
}
}
答案:
1.首先要将方法给解出来:
type MethodName<T> = {
[F in keyof T]: T[F] extends Function ? F : never;
}[keyof T];
2.其次将源函数和目标函数做一个对比:
type asyncMethod<T, U> = (input: Promise<T>) => Promise<Action<U>>;
// 转化为
type asyncMethodConnected<T, U> = (input: T) => Action<U>;
type syncMethod<T, U> = (action: Action<T>) => Action<U>;
// 转化为
type syncMethodConnected<T, U> = (action: T) => Action<U>;
3.用infer来推导类型,做转发:
type EffectMethodAssign<T> = T extends asyncMethod<infer U, infer V> ? asyncMethodConnected<U, V> : T extends syncMethod<infer U, infer V> ? syncMethodConnected<U, V> : never;
4.将两个优化结合:
type Connect = (module: EffectModule) => {
[F in MethodName<typeof module>]: EffectMethodAssign<typeof module[F]>
};
联合类型
type UnionToIntersection<U> =
(U extends any ? (k: U) => void : never) extends ((k: infer I) => void) ? I : never;
function mixIt<T extends any[]>(...args: T): UnionToIntersection<T[number]>{
let mixin: any = {};
args.forEach( obj => {
for(let key in obj) {
if( ! mixin.hasOwnProperty(key) ) {
mixin[key] = obj[key];
}
}
});
return mixin;
}
class X {x: number = 7;}
class Y {y: string = 'ok';}
class Z {z: boolean = false;}
let x = new X;
let y = new Y;
let z = new Z;
let xy = mixIt(x, y);
let xyz = mixIt(x, y, z);
解构
class Plugin {}
class LandingPlugin extends Plugin {
a: string;
}
class ShareCore extends Plugin {
b: string;
}
interface PluginConfig<M> {
config?: any;
bindings?: Array<keyof M>;
};
export type PluginOption<M> = [ConstructorOf<M>, PluginConfig<M>?, any?, boolean?];
function ReinforcePage5<T extends Plugin[]>(c: {
pluginOptions: [
...{[K in keyof T]: PluginOption<T[K]>}
]
}): void {};
ReinforcePage5({
pluginOptions: [
[LandingPlugin, {
bindings: ['a']
}],
[ShareCore, {
bindings: ['b']
}]
]
});