用过python str.format
的肯定觉得java的String.format
弱到爆了,几乎和c的printf一个级别了,很难想象这是一个现代高级语言。让我们封装一个好用的format吧。
import java.util.Map;
public class XString {
/**
* list args偏移从0开始
* dict args放在后面,放在倒数第一、倒数第二这样的,类型为Map<String, Object>
*/
@SuppressWarnings("unchecked")
public static String format(String formater, Object... args) {
StringBuilder builder = new StringBuilder();
int listArgsEndPos = args.length - 1;
for (int argCursor = args.length - 1; argCursor >= 0; -- argCursor) {
Object argProber = args[argCursor];
if (argProber instanceof Map) -- listArgsEndPos;
}
int cursor = 0;
int leftMarkPos = formater.indexOf('{', cursor);
while (leftMarkPos != -1) {
int rightMarkPos = formater.indexOf('}', leftMarkPos + 1);
if (rightMarkPos > leftMarkPos + 1) {
// 实例化
String token = formater.substring(leftMarkPos+1, rightMarkPos);
String[] tokenParts = token.split(":");
String tokenName = tokenParts[0];
String tokenFormat = tokenParts.length == 2 ? "%"+tokenParts[1] : "%s";
String instance;
if (tokenName.matches("\\d+")) { // list arg
Integer listArgOffset = Integer.parseInt(tokenName);
if (listArgOffset > listArgsEndPos) {
throw new IllegalArgumentException(String.format("list arg pos(%d) out of bound(%d)", listArgOffset, listArgsEndPos));
}
instance = String.format(tokenFormat, args[listArgOffset]);
} else if (tokenName.matches("[a-zA-Z][a-zA-Z0-9_]*")) { // dict arg
Object dictArg = null;
for (int dictArgsCursor = listArgsEndPos + 1; dictArgsCursor < args.length; ++ dictArgsCursor) {
dictArg = ((Map<String, Object>) args[dictArgsCursor]).get(tokenName);
if (dictArg != null) break;
}
if (dictArg == null) {
throw new IllegalArgumentException(String.format("formater: (%s), dict arg: (%s) not found", formater, tokenName));
}
instance = String.format(tokenFormat, dictArg);
} else {
instance = formater.substring(leftMarkPos, rightMarkPos + 1);
}
builder.append(formater, cursor, leftMarkPos);
builder.append(instance);
cursor = rightMarkPos + 1;
} else {
builder.append(formater, cursor, leftMarkPos + 1);
cursor = leftMarkPos + 1;
}
leftMarkPos = formater.indexOf('{', cursor);
}
builder.append(formater, cursor, formater.length());
return builder.toString();
}
}
来看一个例子:
Map<String, Object> dictArgs1 = new HashMap<>();
dictArgs1.put("name", "zig");
Map<String, Object> dictArgs2 = new HashMap<>();
dictArgs2.put("age", 27);
System.out.println(XString.format("{{}}, i am a {0}, my name is: {name}, my age is: {age:4d}; a {0} is {age} year(s) old called {name}",
"man", dictArgs1, dictArgs2));