1.问题描述
2.代码
3.总结
一、问题描述:
Description:
Given: an array containing hashes of names
Return: a string formatted as a list of names separated by commas except for the last two names, which should be separated by an ampersand.
Example:
namelist([ {'name': 'Bart'}, {'name': 'Lisa'}, {'name': 'Maggie'} ])
# returns 'Bart, Lisa & Maggie'
namelist([ {'name': 'Bart'}, {'name': 'Lisa'} ])
# returns 'Bart & Lisa'
namelist([ {'name': 'Bart'} ])
# returns 'Bart'
namelist([])
# returns ''
二、代码:
** My solution **(我的方法是真的chun，o)
def namelist(names):
onlyName = []
for item in names:
onlyName.append(item.get('name'))
if len(onlyName) == 0 :
return ""
elif len(onlyName) == 1:
return onlyName[0]
elif len(onlyName) == 2:
return ' & '.join(onlyName)
else:
partOne = onlyName[0:len(onlyName)-2]
partTwo = onlyName[len(onlyName)-2 : len(onlyName)]
p1 = ', '.join(partOne)
p2 = ' & '.join(partTwo)
p = [p1, p2]
return ', '.join(p)
** Other Solutions **
- Best Practices
def namelist(names):
if len(names) > 1:
return '{} & {}'.format(', '.join(name['name'] for name in names[:-1]),
names[-1]['name'])
elif names:
return names[0]['name']
else:
return ''
- Clever
def namelist(names):
return ", ".join([name["name"] for name in names])[::-1].replace(",", "& ",1)[::-1]
