1 使用 future的模块
python3.x 引入了一些与python2.x不兼容的关键字和特性。2.x中可以通过future模块导入新的内容
2 print函数
2.x中print是个语句，3.x中print是个方法，也是说2.x中print 或者print() 、print () 都是可以的，
print "magedu.com"
print("magedu.com")
print ("magedu.com")
不过3.x中print一定要方法的形式调用
print("magedu.com")
3 整数除法
python2.x
>>> 1/2
0
python3.x
>>> 1/2
0.5
>>> 1/0
4 Unicode
- python2.x：ASCII的str类型，有unicode() 转成unicode类型
Python 2.7.16 (default, Apr 17 2020, 18:29:03)
[GCC 4.2.1 Compatible Apple LLVM 11.0.3 (clang-1103.0.29.20) (-macos10.15-objc- on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.getdefaultencoding()
'ascii'
- python3.x：Unicode(utf-8)类型str，bytes，bytearrays
Python 3.7.3 (default, Mar 7 2020, 00:16:22)
[Clang 11.0.0 (clang-1100.0.33.16)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.getdefaultencoding()
'utf-8'
>>>
5 xrange
- python2.x xrange，是个xrange对象
- python3.x range，使用xrange会有异常，range是个range对象
6 异常
- python2.x 支持两种格式
Python 2.7.16 (default, Apr 17 2020, 18:29:03)
[GCC 4.2.1 Compatible Apple LLVM 11.0.3 (clang-1103.0.29.20) (-macos10.15-objc- on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> try:
... a = raw_input("输入一个数：")
... if not a.isdigit():
... raise ValueError("a 必须是数字")
... except ValueError as e:
... print("引发异常：",e)
...
输入一个数：a
('\xe5\xbc\x95\xe5\x8f\x91\xe5\xbc\x82\xe5\xb8\xb8\xef\xbc\x9a', ValueError('a \xe5\xbf\x85\xe9\xa1\xbb\xe6\x98\xaf\xe6\x95\xb0\xe5\xad\x97',))
>>> try:
... a = raw_input("输入一个数：")
... if not a.isdigit():
... raise ValueError("a 必须是数字")
... except ValueError,e:
... print("引发异常：",e)
...
输入一个数：a
('\xe5\xbc\x95\xe5\x8f\x91\xe5\xbc\x82\xe5\xb8\xb8\xef\xbc\x9a', ValueError('a \xe5\xbf\x85\xe9\xa1\xbb\xe6\x98\xaf\xe6\x95\xb0\xe5\xad\x97',))
- python3.x 只支持as e的这种
Python 3.7.3 (default, Mar 7 2020, 00:16:22)
[Clang 11.0.0 (clang-1100.0.33.16)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> try:
... a = input("输入一个数：")
... if not a.isdigit():
... raise ValueError("a 必须是数字")
... except ValueError as e:
... print("引发异常：",e)
...
输入一个数：a
引发异常： a 必须是数字
>>>
7 next方法
- python2.x next() 或者.next()
- python3.x next()
__next__
8 input方法
- python2.x raw_input()
- python3.x input()
9 iter和list
- python2.x 有些迭代对象直接转成list了:dict.key(),dict.values(), map, reduce,filter等等
Python 2.7.16 (default, Apr 17 2020, 18:29:03)
[GCC 4.2.1 Compatible Apple LLVM 11.0.3 (clang-1103.0.29.20) (-macos10.15-objc- on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> lst = map(lambda x:int(x), [x for x in "123456789"])
>>> type(lst)
<type 'list'>
>>> lst
[1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> dt = {x:x for x in range(10)}
>>> dt.values()
dict_values([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
>>> dt.keys()
dict_keys([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
>>> dt.items()
dict_items([(0, 0), (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6), (7, 7), (8, 8), (9, 9)])
>>>
- python3.x 默认返回的是可迭代对象:dict.key(),dict.values(), map, reduce,filter等等
Python 3.7.3 (default, Mar 7 2020, 00:16:22)
[Clang 11.0.0 (clang-1100.0.33.16)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> lst = map(lambda x:int(x), [x for x in "123456789"])
>>> type(lst)
<class 'map'>
>>> lst
<map object at 0x10457a128>
>>>
>>> dt = {x:x for x in range(10)}
>>> dt.values()
dict_values([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
>>> dt.keys()
dict_keys([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
>>> dt.items()
dict_items([(0, 0), (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6), (7, 7), (8, 8), (9, 9)])
>>>
10 字典
- python2.x 字典插入无序
Python 2.7.16 (default, Apr 17 2020, 18:29:03)
[GCC 4.2.1 Compatible Apple LLVM 11.0.3 (clang-1103.0.29.20) (-macos10.15-objc- on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> dt = {}
>>> dt["a"] = "A"
>>> dt["b"] = "B"
>>> dt["c"] = "C"
>>> dt
{'a': 'A', 'c': 'C', 'b': 'B'}
>>>
- python3.5以后，字典插入有序
>>> dt = {}
>>> dt["a"] = "A"
>>> dt["b"] = "B"
>>> dt["c"] = "C"
>>> dt
{'a': 'A', 'b': 'B', 'c': 'C'}
>>>
11 字符串格式化
- python2.x %
>>> a = "%d+%d=%d" %(1,2,3)
>>> a
'1+2=3'
- python3.x format 和f
Python 3.7.3 (default, Mar 7 2020, 00:16:22)
[Clang 11.0.0 (clang-1100.0.33.16)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> a = "{}+{}={}".format(1,2,3)
>>> a
'1+2=3'
>>> a = 1
>>> b = 2
>>> c = 3
>>> d = f"{a}+{b}={c}"
>>> d
'1+2=3'
12 True和False
- python2.x True 可以被赋值
Python 2.7.16 (default, Apr 17 2020, 18:29:03)
[GCC 4.2.1 Compatible Apple LLVM 11.0.3 (clang-1103.0.29.20) (-macos10.15-objc- on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> True + True
2
>>> True = 0
>>> True + True
0
>>>
- python3.x True是关键字
Python 3.7.3 (default, Mar 7 2020, 00:16:22)
[Clang 11.0.0 (clang-1100.0.33.16)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> True+True
2
>>> True = 0
File "<stdin>", line 1
SyntaxError: can't assign to keyword
>>>
python2.x 里面 while 1 要比while True 速度快一些(来自你像从前一样的Python学习笔记-python天坑系列)
➜ Desktop cat python2.py
#! /usr/bin/python
# -*- coding: utf-8 -*-
import timeit
def while_one():
i = 0
while 1:
i += 1
if i == 10000000:
break
def while_true():
i = 0
while True:
i += 1
if i == 10000000:
break
if __name__ == "__main__":
w1 = timeit.timeit(while_one, "from __main__ import while_one", number=3)
wt = timeit.timeit(while_true, "from __main__ import while_true", number=3)
print "while one: %s\nwhile_true: %s" % (w1, wt)
➜ Desktop python python2.py
while one: 0.646219015121
while_true: 1.01446509361
