JavaScript

针对那道题，我是这么想的：

先判断是否为3 and 5 and 7的公倍数，若不是接着判断，为3 and 5、3 and 7、5 and 7的公倍数，若不是则接着判断是否为3、5、7的倍数······

代码：

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function run(num){

if(num%3==0 && num%==0 && num%7==0)

return 'FizzBuzzWhizz';

else if(num%3==0 && num%5==0)

return 'FizzBuzz';

else if(num%5==0 && num%7==0)

return 'BuzzWhizz';

else if(num%3==0 && num%7==0)

return 'FizzWhizz';

else if(num%3==0)

return 'Fizz';

else if(num%5==0)

return 'Buzz';

else if(num%7==0)

return 'Whizz';

else

return num.toString();

}

测试Test：

---

var test1 = function() {

let result = run(2);

if(result != 2) {

document.write('The test 1 failed')}

else {

document.write('The test 1 result is : '+ result)}}

test1()

var test2 = function() {

let result = run(3);

if(result != 'Fizz') {

document.write('The test 2 failed')}

else {

document.write('The test 2 result is : '+ result)}}

test2()

var test3 = function() {

let result = run(5);

if(result != 'Buzz') {

document.write('The test 3 failed')}

else {

document.write('The test 3 result is : '+ result)}}

test3()

var test4 = function() {

let result = run(7);

if(result != 'Whizz') {

document.write('The test 4 failed')}

else {

document.write('The test 4 result is : '+ result)}}

test4()

var test5 = function() {

let result = run(15);

if(result != 'FizzBuzz') {

document.write('The test 5 failed')}

else {

document.write('The test 5 result is : '+ result)}}

test5()

var test6 = function() {

let result = run(21);

if(result != 'FizzWhizz') {

document.write('The test 6 failed')}

else {

document.write('The test 6 result is : '+ result)}}

test6()

var test7 = function() {

let result = run(35);

if(result != 'BuzzWhizz') {

document.write('The test 7 failed')}

else {

document.write('The test 7 result is : '+ result)}}

test7()

var test8 = function() {

let result = run(105);

if(result != 'FizzBuzzWhizz') {

document.write('The test 8 failed')}

else {

document.write('The test8 result is : '+ result)}}

test8()