>>>a = [1,2,3]
>>> b = [4,5,6]
>>> c = [4,5,6,7,8]
>>> zipped = zip(a,b) # 返回一个对象
>>> zipped<zip object at 0x103abc288>
>>> list(zipped) # list() 转换为列表[(1, 4), (2, 5), (3, 6)]
>>> list(zip(a,c)) # 元素个数与最短的列表一致[(1, 4), (2, 5), (3, 6)]
>>> a1, a2 = zip(*zip(a,b)) # 与 zip 相反，zip(*) 可理解为解压，返回二维矩阵式
>>> list(a1)[1, 2, 3]
>>> list(a2)[4, 5, 6]
