原题链接:https://leetcode.com/problems/implement-queue-using-stacks/
Implement the following operations of a queue using stacks.
push(x) -- Push element x to the back of queue.
pop() -- Removes the element from in front of queue.
peek() -- Get the front element.
empty() -- Return whether the queue is empty.
Example:
MyQueue queue = new MyQueue();
queue.push(1);
queue.push(2);
queue.peek(); // returns 1
queue.pop(); // returns 1
queue.empty(); // returns false
Notes:
You must use only standard operations of a stack -- which means only push to top, peek/pop from top, size, and is empty operations are valid.
Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
每次入栈只需要往enstack中入栈,出栈或查看栈顶值时,先判断destack中是否有值, 若有则可直接出栈,因为在enstack中的值肯定比destack中晚入栈。 若没有,则把enstack值全部入栈至destack中,再让destack栈顶值出栈。
class MyQueue:
def __init__(self):
"""
Initialize your data structure here.
"""
self.enstack = []
self.destack = []
def push(self, x: int) -> None:
"""
Push element x to the back of queue.
"""
self.enstack.append(x)
def pop(self) -> int:
"""
Removes the element from in front of queue and returns that element.
"""
while self.destack:
return self.destack.pop()
while self.enstack:
self.destack.append(self.enstack.pop())
return self.destack.pop()
def peek(self) -> int:
"""
Get the front element.
"""
while self.destack:
return self.destack[-1]
while self.enstack:
self.destack.append(self.enstack.pop())
return self.destack[-1]
def empty(self) -> bool:
"""
Returns whether the queue is empty.
"""
return not (self.enstack or self.destack)