break: 跳出循环, 无论循环保持条件是否还为真都不会再执行循环
continue: 跳出本次循环, 如果循环保持条件还为真还会继续执行循环
OC:
NSArray *arr = @[@1,@3, @5, @7, @8];
for (NSNumber *num in arr) {
if ([num isEqualTo:@(7)]) {
NSLog(@"找到幸运数字");
break;
}
NSLog(@"没有找到幸运数字");
}
NSArray *arr = @[@1,@3, @5, @7, @8];
int count = 0;
for (NSNumber *num in arr) {
if (num.intValue % 2 != 0 ) {
NSLog(@"不能被2整除");
continue;
}
NSLog(@"能被2整除");
count++;
}
NSLog(@"count = %d", count);
swift:
var arr:Array<Int> = [1, 3, 5, 7, 8]
for num in arr{
if num == 7
{
print("找到幸运数字")
break
}
print("没有找到幸运数字")
}
var arr1:Array<Int> = [1, 3, 5, 7, 8]
var count:Int = 0
for num in arr1{
if num % 2 != 0
{
print("不能被2整除")
continue
}
print("能被2整除")
count++
}
print("count = \(count)")
