No BB,直接上代码示例：

        String str = "沙比修仙传第7279章56回";
        String str = "https://www.java.com/id65536/";
        String str = "https://www.jj.com/notebooks/28048652/notes/53919505";
        String regex = "\\d*";
        Pattern pattern = Pattern.compile(regex);
        Matcher match= pattern.matcher(str);
        while (match.find()) {
            if (!"".equals(match.group()))
                System.out.println("出来吧，数字们:   " + match.group());
        }

下面提供更多的方法


// 判断一个字符串是否都为数字  
public boolean isDigit(String strNum) {  
    return strNum.matches("[0-9]{1,}");  
}  
  
// 判断一个字符串是否都为数字  
public boolean isDigit(String strNum) {  
    Pattern pattern = Pattern.compile("[0-9]{1,}");  
    Matcher matcher = pattern.matcher((CharSequence) strNum);  
    return matcher.matches();  
}
 
//截取数字  
public String getNumbers(String content) {  
    Pattern pattern = Pattern.compile("\\d+");  
    Matcher matcher = pattern.matcher(content);  
    while (matcher.find()) {  
       return matcher.group(0);  
    }  
    return "";  
}  
  
// 截取非数字  
public String splitNotNumber(String content) {  
    Pattern pattern = Pattern.compile("\\D+");  
    Matcher matcher = pattern.matcher(content);  
    while (matcher.find()) {  
        return matcher.group(0);  
    }  
    return "";  
}
  
// 判断一个字符串是否含有数字
public boolean HasDigit(String content) {
    boolean flag = false;
    Pattern p = Pattern.compile(".*\\d+.*");
    Matcher m = p.matcher(content);
    if (m.matches()) {
        flag = true;
    }
    return flag;
}


判断字符串是否已数字开头
String str = "a40###2";
System.out.println(str.matches("^\\d+?.*$"));

我们从网上爬下来的文件很多时候都是带着<br>之类的格式化标签
content = content.replace('<br/>', '\n')

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