You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Example
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Explanation: 342 + 465 = 807.
C++代码
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
ListNode* res;
res = new ListNode(-1);
int temp=0;
ListNode* tmp = res;
ListNode* p1 = l1;
ListNode* p2 = l2;
while(p1 != NULL || p2 != NULL){
int sum = temp;
if(p1 != NULL){
sum += p1->val;
p1 = p1->next;
}
if(p2 != NULL){
sum += p2->val;
p2 = p2->next;
}
tmp->next = new ListNode(sum%10);
temp = sum/10;
tmp = tmp->next;
}
if(temp) tmp->next = new ListNode(1);
return res->next;
}
};
