使用 UI_USER_INTERFACE_IDIOM()进行区分 (iOS3.2 >=) 无法区分iphone和ipod
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
// <define your constants here>
} else {
// <define your constants here>
}
区分目前UI_USER_INTERFACE_IDIOM()有2个返回值
UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad
UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone ```
使用 UIDevice.model 进行区分 ([ios](http://lib.csdn.net/base/ios) 2.0 >=)
NSString *deviceType = [UIDevice currentDevice].model;
if([deviceType isEqualToString:@"iPhone"]) {
//iPhone
}
else if([deviceType isEqualToString:@"iPod touch"]) {
//iPod Touch
}
else {
//iPad
}
使用系统的一个函数sysctlbyname 来获取设备名称
- (NSString *) platformString
{
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *machine = malloc(size);
sysctlbyname("hw.machine", machine, &size, NULL, 0);
NSString *platform = [NSString stringWithUTF8String:machine];
free(machine);
if ([platform isEqualToString:@"iPhone1,1"]) return @"iPhone 1G";
if ([platform isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
if ([platform isEqualToString:@"iPhone2,1"]) return @"iPhone 3GS";
if ([platform isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
if ([platform isEqualToString:@"iPhone3,3"]) return @"Verizon iPhone 4";
if ([platform isEqualToString:@"iPod1,1"]) return @"iPod Touch 1G";
if ([platform isEqualToString:@"iPod2,1"]) return @"iPod Touch 2G";
if ([platform isEqualToString:@"iPod3,1"]) return @"iPod Touch 3G";
if ([platform isEqualToString:@"iPod4,1"]) return @"iPod Touch 4G";
if ([platform isEqualToString:@"iPad1,1"]) return @"iPad";
if ([platform isEqualToString:@"iPad2,1"]) return @"iPad 2 (WiFi)";
if ([platform isEqualToString:@"iPad2,2"]) return @"iPad 2 (GSM)";
if ([platform isEqualToString:@"iPad2,3"]) return @"iPad 2 (CDMA)";
if ([platform isEqualToString:@"i386"]) return @"Simulator";
return @"";
}```
转自文章
