1.引子
假如已经从A走到E了, 现在要求从E走到D,用时最短怎么办?
传统的循环链表只是从A->E->A->D, 但是现在明明可以只要E回退一步就到了D,何必那么麻烦呢
这就需要用到一个指针 告诉E下一步需要走到D, 这个指针就是前驱指针.
也就引入了今天要介绍的双向链表
双向链表是在单链表的每个结点中,再设置一个指向其前驱结点的指针。
2.代码
#include <stdio.h>
#include <stdlib.h>
#define OK 1
#define ERROR 0
#define TRUE 1
#define FALSE 0
typedef int Status;
typedef int ElementType;
typedef struct node {
ElementType data;
struct node *prior,*next;
} Node, *DoubleLinkList;
void InitDLLinkList(DoubleLinkList *list) {
*list = (DoubleLinkList)malloc(sizeof(Node));
(*list)->next = NULL;
(*list)->prior = NULL;
}
void createDLinkList(DoubleLinkList list, int n) {
DoubleLinkList p;
p = list;
for (int i = 1; i <= n; i++) {
DoubleLinkList tempNode = (DoubleLinkList)malloc(sizeof(Node));
tempNode->data = i;
//将新结点的next和pror指针 与先后结点都建立关系
p->next = tempNode;
tempNode->prior = p;
p = tempNode;
}
//将最后一个结点的next指向链表的头部, 并将链表的前驱指针指向最后一个指针 形成双向循环链表
p->next = list;
list->prior = p;
}
//求双向链表的长度 - 最后一个结点不等于头结点
int DLLinkLength(DoubleLinkList list) {
int allCount = 0;
DoubleLinkList moveNode = list->next;
while (moveNode != list) {
moveNode = moveNode->next;
allCount++;
}
return allCount;
}
//遍历 - 正序
void IteratorDLLinkList(DoubleLinkList list) {
DoubleLinkList moveNode = list->next;
int k = 0;
while (moveNode != list) {
printf("current is %d\n",moveNode->data);
moveNode = moveNode->next;
k++;
}
}
//遍历 - 倒序
void reverse_itemratorList(DoubleLinkList list) {
DoubleLinkList move = list->prior;
int k = 0;
while (move != list) {
printf("current is %d\n",move->data);
move = move->prior;
k++;
}
}
/** 插入情况是考虑已经初始化和创建过链表了*/
Status insert_Node_DLList(DoubleLinkList list, int i, ElementType e) {
int length = DLLinkLength(list);
DoubleLinkList insertNode = malloc(sizeof(Node));
insertNode->data = e;
if (i < 0 || i > length+1) {
return ERROR;
}
if (i == 0) {
//1.将新结点的next指向 头结点的next(即第一个存放数据的结点,此处可能为null)
insertNode->next = list->next;
//2.将头结点下一个结点的前驱指针 指向当前的插入结点
list->next->prior = insertNode;
//3.将头结点的next指针指向新结点
list->next = insertNode;
//4.将新节点的前驱指针指向头结点
insertNode->prior = list;
} else if (i == length+1) {
//0.通过链表的前驱结点找到最后一个结点
DoubleLinkList currentLast = list->prior;
//1.将最后一个结点的next指针指向新节点
currentLast->next = insertNode;
//2.将新结点的前驱指针 指向当前最后一个结点
insertNode->prior = currentLast;
//3.因为当前新节点成为了最后一个结点了, 所以新结点的next指针指向头结点
insertNode->next = list;
//4.将头结点的前驱指针 指向新结点
list->prior = insertNode;
} else {
int currentIndex;
DoubleLinkList currentNode = list;
//0. 找到第i-1个位置的结点
for (currentIndex = 1; currentIndex < i; currentIndex++) {
currentNode = currentNode->next;
}
//1.将新结点的next指针 指向当前i位置的结点
insertNode->next = currentNode->next;
//2.将当前i位置结点的前驱指针 指向要插入的结点
currentNode->next->prior = insertNode;
//3.将第i-1个位置的next指针 指向新创建的结点
currentNode->next = insertNode;
//4.将新创建结点的前驱指针 指向第i-1个位置的结点
insertNode->prior = currentNode;
}
return OK;
}
/** 删除(i)结点 相当于直接将 (i-1)结点的指针直接指向第 (i+1)个结点*/
int delete_node(DoubleLinkList list, int k) {
int allCount = DLLinkLength(list);
if (k < 0 || allCount < k) {
return ERROR;
}
DoubleLinkList moveNode = list;
DoubleLinkList deleteNode = list->next;
if (k == 0) {
//头结点的next指针 直接指向删除结点的下一个结点
moveNode->next = deleteNode->next;
deleteNode->next->prior = moveNode;
} else if(k == allCount) {
//因为要删除最后一个结点 所以直接通过头结点的前驱结点找到要删除的结点
deleteNode = list->prior;
//根据要删除的结点的前驱结点 找到第k-1个结点
moveNode = deleteNode->prior;
//剩下两步是绑定next和前驱指针
moveNode->next = deleteNode->next;
deleteNode->next->prior = moveNode->next;
printf("删除了");
} else {
//找到第k-1个结点
for (int i = 1; i < k; i++) {
moveNode = moveNode->next;
}
//找到要删除的第k个结点
deleteNode = moveNode->next;
moveNode->next = deleteNode->next;
deleteNode->next->prior = moveNode;
}
return OK;
}
void print_data(DoubleLinkList list) {
IteratorDLLinkList(list);
printf("length is %d\n",DLLinkLength(list));
printf("\n\n");
}
void print_reverse_data(DoubleLinkList list) {
reverse_itemratorList(list);
printf("length is %d\n",DLLinkLength(list));
printf("\n\n");
}
#pragma mark - 使用
void k_check_DoubleLink(void) {
DoubleLinkList list;
InitDLLinkList(&list);
createDLinkList(list, 9);
insert_Node_DLList(list, 0, 12);
print_data(list);
insert_Node_DLList(list, 5, 22);
print_reverse_data(list);
delete_node(list, 9);
IteratorDLLinkList(list);
}