Given a positive integer num, write a function which returns True if num is a perfect square else False.
Note:Do not use any built-in library function such as sqrt.
Example 1:
Input: 16
Returns: True
Example 2:
Input: 14
Returns: False
给定正整数num，编写函数，返回num是否为平方数，要求不使用内置标准库函数。
思路
数学解法
1 = 1
4 = 1 + 3
9 = 1 + 3 + 5
16 = 1 + 3 + 5 + 7
25 = 1 + 3 + 5 + 7 + 9
36 = 1 + 3 + 5 + 7 + 9 + 11
....
1+3+...+(2n-1) = (2n-1 + 1)m/2 = mn （其中m为项数 ）
class Solution {
public:
bool isPerfectSquare(int num) {
int i = 1;
while (num > 0) {
num -= i;
i += 2;
}
return num == 0;
}
};
