ListView 适配器Adapter getView 优化
场景:展示Sever Get到的数据 数据中要展示的Item数据类型不确定 需要两个以上的展示形式
解决办法
- 1,实现Base Adapter的 getItemViewType() 方法 getViewTypeCount() 方法
- 2,在getView() 方法中通过getItemViewType()方法获取当前要展示的Item类型是哪一类
根据不同的Type实例化不同的ViewHolder contentView.setTag() getTag() 复用当前缓存的
viewHolder
package com.ming.listviewadapterdemo.adapter;
import android.content.Context;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.BaseAdapter;
import java.util.ArrayList;
/**
* Created by 明正 on 2017/3/26.
*/
public abstract class DefaultAdapter<T> extends BaseAdapter {
private static final int TYPE_ONE = 0;
private static final int TYPE_TWO = 1;
private ArrayList<T> mList;
private Context mContext;
public DefaultAdapter(ArrayList<T> list, Context context) {
mList = list;
mContext = context;
}
/**
* How many items are in the data set represented by this Adapter.
*
* @return Count of items.
*/
@Override
public int getCount() {
return mList!=null?mList.size():0;
}
/**
* Get the data item associated with the specified position in the data set.
*
* @param position Position of the item whose data we want within the adapter's
* data set.
* @return The data at the specified position.
*/
@Override
public Object getItem(int position) {
return mList!=null?mList.get(position):null;
}
/**
* Get the row id associated with the specified position in the list.
*
* @param position The position of the item within the adapter's data set whose row id we want.
* @return The id of the item at the specified position.
*/
@Override
public long getItemId(int position) {
return position;
}
/**
* Get a View that displays the data at the specified position in the data set. You can either
* create a View manually or inflate it from an XML layout file. When the View is inflated, the
* parent View (GridView, ListView...) will apply default layout parameters unless you use
* {@link LayoutInflater#inflate(int, ViewGroup, boolean)}
* to specify a root view and to prevent attachment to the root.
*
* @param position The position of the item within the adapter's data set of the item whose view
* we want.
* @param convertView The old view to reuse, if possible. Note: You should check that this view
* is non-null and of an appropriate type before using. If it is not possible to convert
* this view to display the correct data, this method can create a new view.
* Heterogeneous lists can specify their number of view types, so that this View is
* always of the right type (see {@link #getViewTypeCount()} and
* {@link #getItemViewType(int)}).
* @param parent The parent that this view will eventually be attached to
* @return A View corresponding to the data at the specified position.
*/
@Override
public View getView(int position, View convertView, ViewGroup parent) {
ViewHolderOne viewHolderOne = null;
ViewHolerTwo viewHolerTwo = null;
if(convertView==null){
//加载xml布局
switch (getItemViewType(position)){
case TYPE_ONE:
viewHolderOne = new ViewHolderOne();
convertView.setTag(viewHolderOne);
break;
case TYPE_TWO:
viewHolerTwo = new ViewHolerTwo();
convertView.setTag(viewHolerTwo);
break;
}
}else switch (getItemViewType(position)) {
case TYPE_ONE:
viewHolderOne = (ViewHolderOne) convertView.getTag();
break;
case TYPE_TWO:
viewHolerTwo = (ViewHolerTwo) convertView.getTag();
break;
}
return convertView;
}
@Override
public int getItemViewType(int position) {
if(position!=0){
return TYPE_TWO;
}else {
return TYPE_ONE;
}
}
@Override
public int getViewTypeCount() {
return 2;
}
class ViewHolderOne {
public ViewHolderOne(View contentView) {
initView(contentView);
}
private void initView(View view) {
}
}
class ViewHolerTwo {
public ViewHolerTwo(View contentView) {
initView(contentView);
}
private void initView(View view) {
}
}