LeetCode 排列组合 题目汇总
LeetCode 数字 题目汇总
LeetCode 动态规划 题目分类汇总
干货！LeetCode 题解汇总
题目描述
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Note:
0 ≤ x, y < 2^31.
Example:
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
分析
题目可以理解为：求两个数有多少位是不一样的。那么步骤可以为：
- 将两个数异或，结果记为 val
- 计算 val 有多少个 1
代码
public int hammingDistance(int x, int y) {
int val = x ^ y;
int result = 0;
while (val != 0) {
if ((val & 1) == 1) {
result++;
}
val >>= 1;
}
return result;
}
