https://leetcode.com/problems/reverse-integer/description/
输入: 32位有符号 int
输出: 逆序
思路:
循环取余就可以实现了,需要注意溢出的情况
class Solution {
public int reverse(int x) {
int t = x;
int num = 0;
while(t!=0){
int temp = num*10 + t%10;
if((temp-t%10)/10 != num){
return 0;
}
num = temp;
t=t/10;
}
return num;
}
}
