1.Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0
2.题目要求：搜索插入位置，即找出比当前数字小的数字个数。
3.方法：遍历一遍原数组，若当前数字大于或等于目标值，则返回当前坐标，如果遍历结束了，说明目标值比数组中任何一个数都要大，则返回数组长度n即可
4.代码：
class Solution {
public:
int searchInsert(vector<int>& nums, int target) {
for (int i = 0; i < nums.size(); ++i) {
if (nums[i] >= target) return i;
}
return nums.size();
}
};
