Problem Description
Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

Input
each test case contains two numbers A and B.

Output
for each case, if A is equal to B, you should print "YES", or print "NO".

Sample Input
1 2
2 2
3 3
4 3

Sample Output
NO
YES
YES
NO

我认为这道题对于我这样的初学者来说很容易犯用double型变量储存数据的错误，其实不然这道题可能要求输入的数据并不是简单的数像1.111这样的也可能是001.111、001.11100、-001.111 、+001.111这样的数，所以我在这里用到了用string 类型的变量储存数据在对变量进行处理后进行比较。

//代码

#include<iostream>
#include<string>
using namespace std;
string Simp(string a)//实现输入数字的整合，去掉无用的“0”
{
    string a1;
    int c = 0, d=a.length(), e, f = 0, g = 0;
    for (int i = 0; i < a.length(); i++)//判断是否有小数点，并且记住小数点的位置
    {
        if (a[i] == '.')
        {
            c = 1;
            d = i;
            break;
        }
    }
    if (c ==1)
    {
        if (a[0] == '-' || a[0] == '+')
        {
            a1 += a[0];
            g++;
        }
        for (int i = g; i<d; i++)
        {
            if (a[i] != '0')
            {
                f = 1;
                e = i;
            }
        }
        if (f ==1)
        {
            for (int i = e; i < d; i++)
            {
                a1 += a[i];
                g++;
            }
        }
        if (f == 0)
        {
            a1 += '0';
            g++;
        }//除去小数点前的无用“0”
        int h = d;
        for (int i = d + 1; i < a.length(); i++)
        {
            if (a[i] != '0')
            {
                h = i;
            }
        }
        if (h != d)
        {
            a1 += '.';
            g++;
            for (int i = d + 1; i <= h; i++)
            {
                a1+= a[i];
                g++;
            }
        }//除去小数点后的无用“0”
    }
    if (c == 0)
    {
        if (a[0] == '-' || a[0] == '+')
        {
            a1 += a[0];
            g++;
        }
        for (int i = g; i<a.length(); i++)
        {
            if (a[i] != '0')
            {
                f = 1;
                e = i;
                break;
            }
        }
        if (f == 1)
        {
            for (int i = e; i < d; i++)
            {
                a1 += a[i];
                g++;
            }
        }
        if (f == 0)
        {
            a1+= '0';
            g++;
        }
    }
    return a1;
}
int Judge(string a, string b)//判断两个数字是否相同
{
    int e = 1;
    if (a[0] != '+' || a[0] != '-')
    {
        a += a[a.length() - 1];
        for (int i = a.length()-2; i >0; i--)
        {
            a[i] = a[i - 1];
        }
        a[0]= '+';
    }
    if (b[0] != '+' || b[0] != '-')
    {
        b += b[b.length() - 1];
        for (int i = b.length(); i >0; i--)
        {
            b[i] = b[i - 1];
        }
        b[0] = '+';
    }//添加“+”号方便判断
    if (a.length() != b.length())
    {
        e = 0;
    }
    if (a.length() == b.length())
    {
        for (int i = 0; i < a.length(); i++)
        {
            if (a[i] != b[i])
            {
                e = 0;
                break;
            }
        }
    }
    return e;
}
int main()
{
    string a,b;
    while (cin >> a >> b)
    {
        string a1, b1;
        a1=Simp(a);
        b1 = Simp(b);
        if (Judge(a1, b1) == 1)
        {
            cout << "YES" << endl;
        }
        if (Judge(a1, b1) == 0)
        {
            cout << "NO" << endl;
        }
    }
}