Find the total area covered by two rectilinear rectangles in a 2D plane.
Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.
Rectangle Area
Assume that the total area is never beyond the maximum possible value of int.
一刷
两个矩形面积相加减去overlap
public class Solution {
public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
int areaOfSqrA = (C - A) * (D - B);//ABCD
int areaOfSqrB = (G - E) * (H - F);//EFGH
int left = Math.max(A, E);
int right = Math.min(G, C);
int bottom = Math.max(F, B);
int top = Math.min(D, H);
int overlap = 0;
if(right>left && top>bottom){
overlap = (right - left) * (top - bottom);
}
return areaOfSqrA + areaOfSqrB - overlap;
}
}
