Question
把数组所有的值为0的元素移到末尾
Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.
For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].
Note:
You must do this in-place without making a copy of the array.
Minimize the total number of operations.
Solutions
写了个效率很低的
public class Solution {
public void moveZeroes(int[] nums) {
for (int i = 0; i < nums.length; i++) {
if (nums[i] == 0) {
for (int j = i + 1; j < nums.length; j++) {
if (nums[j] != 0) {
nums[i] = nums[j];
nums[j] = 0;
break;
}
}
}
}
}
}
效率高的不会写，就去讨论区研究了下
public class Solution {
public void moveZeroes(int[] nums) {
int index = 0;
for(int i = 0;i<nums.length;i++){
if(nums[i] !=0){
nums[index++] = nums[i];
}
}
for(int i = index;i<nums.length;i++){
nums[i] = 0;
}
}
}
好厉害，佩服佩服
