Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg","add", return true.
Given "foo", "bar", return false.
Given"paper", "title", return true.
Note:
You may assume both s and t have the same length.
题意：判断两个字符串，是否是同构字符串
思路：弄两个数组，循环遍历字符串，判断如果对应位置映射的数字不同那么就return false，否则就给同一位置的字母写入同样的数字，这样就可以判断了。
class Solution {
public boolean isIsomorphic(String s, String t) {
int[] mapS = new int[128];
int[] mapT = new int[128];
for(int i = 0; i < s.length(); i++){
if(mapS[s.charAt(i)] != mapT[t.charAt(i)])
return false;
mapS[s.charAt(i)] = mapT[t.charAt(i)] = i + 1;
}
return true;
}
}
