A - Candy Sharing Game

HDU - 1034

A number of students sit in a circle facing their teacher in the center. Each student initially has an even number of pieces of candy. When the teacher blows a whistle, each student simultaneously gives half of his or her candy to the neighbor on the right. Any student, who ends up with an odd number of pieces of candy, is given another piece by the teacher. The game ends when all students have the same number of pieces of candy.
Write a program which determines the number of times the teacher blows the whistle and the final number of pieces of candy for each student from the amount of candy each child starts with.

Input
The input may describe more than one game. For each game, the input begins with the number N of students, followed by N (even) candy counts for the children counter-clockwise around the circle. The input ends with a student count of 0. Each input number is on a line by itself.

Output
For each game, output the number of rounds of the game followed by the amount of candy each child ends up with, both on one line.

Sample Input
6
36
2
2
2
2
2
11
22
20
18
16
14
12
10
8
6
4
2
4
2
4
6
8
0
Sample Output
15 14
17 22
4 8

Hint
The game ends in a finite number of steps because:

1. The maximum candy count can never increase.
2. The minimum candy count can never decrease.
3. No one with more than the minimum amount will ever decrease to the minimum.
4. If the maximum and minimum candy count are not the same, at least one student with the minimum amount must have their count increase.

题意：小朋友们坐成圈，当老师吹口哨时，每个小朋友把自己一半的糖给右边的人，然后老师给糖数为单数的小朋友一颗糖，重复这个过程，直到所有小朋友糖数相等，求一共吹了多少次口哨，最终每个小朋友几个糖。

解法：水题，一个循环就可以了。

代码：

#include<iostream>
using namespace std;

int main()
{
    int num;
    while(cin>>num&&num!=0){
        int a[100];
        int ans=0;
        for(int i=0;i<num;i++)
            cin>>a[i];
        while(1){
            int flag=1;
            for(int i=1;i<num;i++)
                if(a[i]!=a[i-1])
                    flag=0;
            if(flag==1)
                break;
            int temp=a[0];
            for(int i=0;i<num;i++){
                a[i]/=2;
                if(i==num-1)
                    a[i]+=temp/2;
                else
                    a[i]+=a[i+1]/2;
                if(a[i]%2==1)
                    a[i]++;
            }
            ans++;
        }
        cout<<ans<<" "<<a[0]<<endl;
    }
}