1、编写多线程应用程序，模拟多个人通过一个山洞：
（1）这个山洞每次只能通过一个人，每个人通过山洞的时间为5秒
（2）随机生成10个人，同时准备过此山洞，显示一下每次通过山洞人的姓名
思路:一个山洞(类),10个人(10个线程),只有一个人能通过(当一个线程通过时没其他线程不能运行这个程序,线程锁),
通过时间5秒,即线程sleep 5秒
public class Test02 {
public static void main(String[] args) {
//实例化山洞
Shandong shandong = new Shandong();
//创建10个线程
Thread thread1 = new Thread(shandong, "1");
Thread thread2 = new Thread(shandong, "2");
Thread thread3 = new Thread(shandong, "3");
Thread thread4 = new Thread(shandong, "4");
Thread thread5 = new Thread(shandong, "5");
Thread thread6 = new Thread(shandong, "6");
Thread thread7 = new Thread(shandong, "7");
Thread thread8 = new Thread(shandong, "8");
Thread thread9 = new Thread(shandong, "9");
Thread thread10 = new Thread(shandong, "10");
thread1.start();
thread2.start();
thread3.start();
thread4.start();
thread5.start();
thread6.start();
thread7.start();
thread8.start();
thread9.start();
thread10.start();
}
}
//山洞
class Shandong extends Thread{
@Override
public void run() {
//上锁
synchronized(this){
System.out.println(Thread.currentThread().getName()+"正在通过,请等待5s");
try {
sleep(5000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
